Alternative solution to 'Compare random arrays' plus an explanation

Author: ibah

100 Numpy exercises.ipynb

@@ -855,8 +855,13 @@
    "source": [
     "A = np.random.randint(0,2,5)\n",
     "B = np.random.randint(0,2,5)\n",
+	"# Assuming identical shape of the arrays and a tolerance for the comparison of values"
     "equal = np.allclose(A,B)\n",
     "print(equal)"
+	"\n"
+	"# Checking both the shape and the element values, no tolerance (values have to be exactly equal)"
+	"equal = np.array_equal(A,B)"
+	"print(equal)"
    ]
   },
   {

100 Numpy exercises.md

@@ -387,8 +387,13 @@ np.add.reduce(Z)
 ```python
 A = np.random.randint(0,2,5)
 B = np.random.randint(0,2,5)
+# Assuming identical shape of the arrays and a tolerance for the comparison of values
 equal = np.allclose(A,B)
 print(equal)
+
+# Checking both the shape and the element values, no tolerance (values have to be exactly equal)
+equal = np.array_equal(A,B)
+print(equal)
 ```
 
 #### 43. Make an array immutable (read-only) (★★☆)