Another solution to question 96.

We can use np.unique with axis=0 to return unique rows of an array. For NumPy >= 1.13

Author: kuzand

100_Numpy_exercises.md

@@ -1157,8 +1157,8 @@ _, idx = np.unique(T, return_index=True)
 uZ = Z[idx]
 print(uZ)
 
-# Another solution, for NumPy >= 1.13
 # Author: Andreas Kouzelis
+# For NumPy >= 1.13
 uZ = np.unique(Z, axis=0)
 print(uZ)
 ```